2x^2+84-26x=0

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Solution for 2x^2+84-26x=0 equation: 



2x^2+84-26x=0

a = 2; b = -26; c = +84;
Δ = b2-4ac
Δ = -262-4·2·84
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$


$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-26)-2}{2*2}=\frac{24}{4}
=6
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-26)+2}{2*2}=\frac{28}{4}
=7
$

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